Question

Zinc metal reacts with hydrochloric acid according to the following balanced equation. Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) When 0.119 g...

Zinc metal reacts with hydrochloric acid according to the following balanced equation. Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) When 0.119 g of Zn(s) is combined with enough HCl to make 53.4 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 21.7 ∘C to 24.5 ∘C. Part A Find ΔHrxn for this reaction as written. (Use 1.0 g/mL for the density of the solution and 4.18 J/g⋅∘C as the specific heat capacity.)

Homework Answers

Answer #1

Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)

No of mol of Zn reacted = 0.119/65.5 = 0.00182 mol

heat released during the reaction(q) = m*s*DT

m = mass of solution = v*d + zinc mass

= 53.4*1+0.119 = 53.52 g

S = specific heat capacity of solution = 4.18 j/g,c

DT = 24.5 - 21.7 = 2.8

q = 53.52*4.18*2.8

= 626.4 joule

= 0.6264 kj

Part A

DHrxn = -q/n = -0.6264/0.00182 = -344.176 kj/mol

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

ADVERTISEMENT