Question

For the following reaction, 6.72 grams of carbon (graphite) are mixed with excess oxygen gas . The reaction yields 19.7 grams of carbon dioxide . carbon (graphite)(s) + oxygen(g) carbon dioxide(g) What is the ideal yield of carbon dioxide? grams What is the percent yield for this reaction? %

Answer 1

Ideal yield of CO2 = 24.62g

percent yield of the reation = 80.02%

Explanation

The balanced equation for the reaction is

C(s) + O2(g) -------> CO2(g)

stoichiometrically , 1mole of C gives 1mole of CO2

number of moles = mass /molar mass

number of moles of C = 6.72 g / 12.01g/mol = 0.5595mol

0.5595 moles of C gives 0.5595moles of CO2

mass of CO2 maximum formed = 0.5595mol × 44.01g/mol = 24.62g

Theoretical yield = 24.62g

Actual yield = 19.7g

percent yield = ( Actual yield/ Theoretical yield) ×100

percent yield of the reaction = (19.7g/ 24.62g)× 100 = 80.02%