"In our bodies, sugar is broken down with oxygen to produce water and carbon dioxide." For the following reaction, 4.87 grams of glucose (C6H12O6) are mixed with excess oxygen gas. The reaction yields 6.02 grams of carbon dioxide. glucose (C6H12O6) (s) + oxygen (g) carbon dioxide (g) + water (l) What is the ideal yield of carbon dioxide? grams What is the percent yield for this reaction? %
(C6H12O6) (s) + oxygen (g) ------------> carbon dioxide (g) + water (l)
C6H12O6 (s) + 6 O2 (g) ----------> 6 CO2 (g) + 6 H2O (l)
180.16 g 264.06 g
4.87 g ??
180.2 g glucose ----------> 264 g CO2
4.87 g glucose -----------> ??
ideal yield of CO2 = 4.87 x 264 / 180
ideal yield of CO2 = 7.14 g
percent yield = (actual / ideal) x 100
= (6.02 / 7.14) x 100
percent yield = 84.3 %
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