How do you prepare a 1.0 L buffer with pH 5, using Oxalic acid and its sodium salt(s)?
To prepare a 1.0 L buffer with pH 5, using Oxalic acid and its
mono sodium salt use following steps:
so as we know
pH = pKa + log [salt]/[acid]
Here pH = 5.0 pKa = 4.19
5= 4.19+ log [salt] / [acid]
0.81 = log [salt]/[acid]
taking anitlog...
[salt]/[acid] = 6.46
no. of moles of salt / no. of moles of acid = 6.46
and the molarity = no. of moles of solute / volume of solutionin
litres
so no. of moles of solute = molarity X volume of solution in
litres
as the buffer solution is of 1000 ml or 1.0 L
let acid = x L ...then
salt = 1.0-x L
no. of moles of acid = 1.0*X
no. of moles of salt = 1.0* (1.0-X)
putting in above relation
no. of moles of salt / no. of moles of acid = 6.46
1.0* (1.0-X) / 1.0*X = 6.46
x = 0.134 L
x = volume of acid used 0.134 L or 134 ml
1.0-x = volume of salt used = 0.866 L or 866
ml
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