Question

How many moles of allicin are present in 7.40 mg of this substance?

How many molecules of allicin are in 7.40 mg of this substance?

How many O atoms are present in 7.40 mg of allicin?

Answer 1

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molar mass of allicin = 162.26 gm/ mole

7.40 mg = 0.0074 gm

162.26 gm = 1 mole then 0.0074 gm = 0.0074 / 162.26 = 4.56058 10^-5 mole

7.40 mg allicin = 4.56058 10^-5 mole

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1 mole of substance contain 6.022 10²³ molecule then 4.56058 10^-5 mole allicin present

4.56058 10^-5 6.022 10²³ = 2.7463824 10¹⁹ molecule

7.40 mg allicin present 2.7463824 10¹⁹ molecule

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in 1 molecule of allicin present 1 atom of oxygen therefore 2.7463824 10¹⁹ molecule of allicin present 2.7463824 10¹⁹ atom of oxygen