Question
What is the pH of a saturated solution of Zn(OH)2? Ksp = 1.8 x 10^-14
What is the pH of a saturated solution of Zn(OH)2?
Ksp = 1.8 x 10^-14
Homework Answers
Answer #1
In aq solutions
Zn(OH)2(s)
Zn+2(aq) +
2HO-(aq)
? Ksp =[Zn+2][HO-]2
= 4s3
Therefore Molar solubility , s = Cuberoot (Ksp/4)
= Cube root (1.8*10-14/4)
=1.84*10-5 M
Therefore For [HO- ]
2s = 2*1.84*10-5 M
= 3.68*10-5
Therefore pOH = -log [HO-]
= - log(3.68*10-5)
= 4.43
Since pH = 14 -pOH
= 14 - 4.43
= 9.56
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