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What is the molarity of ZnCl2 that forms when 20.0 g of zinc completely reacts with...

What is the molarity of ZnCl2 that forms when 20.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 260 mL . Zn(s)+CuCl2(aq)→ZnCl2(aq)+Cu(s)

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Answer #1

mass of Zn = 20.0 g

molar mass of Zn = 65.4 g/mol

number of moles of Zn = mass / molar mass

                    = 20.0/65.4

                    = 0.306 mol

moles of ZnCl2 formed = moles of Zn reacted

                  = 0.306 mol

volume = 260 mL = 0.260 L

molarity = number of moles of ZnCl2/ volume

       = 0.306/0.260

       =1.18 M

Answer: 1.18 M

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