Question

A student adds 45.00 grams of zinc metal (cs = 0.377 J/goC) to 115.00 grams of...

A student adds 45.00 grams of zinc metal (cs = 0.377 J/goC) to 115.00 grams of water (cs = 4.184 J/goC). The initial temperature of the metal is 98.00 oC and the initial temperature of the water is 21.00 oC. What is the final temperature of the metal and water?

Homework Answers

Answer #1

m(water) = 115.0 g

T(water) = 21.0 oC

C(water) = 4.184 J/goC

m(metal) = 45.0 g

T(metal) = 98.0 oC

C(metal) = 0.377 J/goC

T = 21.4 oC

We will be using heat conservation equation

Let the final temperature be T oC

use:

heat lost by metal = heat gained by water

m(metal)*C(metal)*(T(metal)-T) = m(water)*C(water)*(T-T(water))

45.0*0.377*(98.0-T) = 115.0*4.184*(T-21.0)

16.965*(98.0-T) = 481.16*(T-21.0)

1662.57 - 16.965*T = 481.16*T - 10104.36

T= 23.6224 oC

Answer: 23.62 oC

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