Question

Be sure to answer all parts.

Fermentation is a complex chemical process of wine making in which glucose is converted into ethanol and carbon dioxide: C₆H₁₂O₆ →2C₂H₅OH + 2CO₂ glucose ethanol

Starting with 755.1 g of glucose, what is the maximum amount of ethanol in grams and in liters that can be obtained by this process (density of ethanol = 0.789 g/mL)?

____ g

_____ L

Answer 1

C6H12O6 →2C2H5OH + 2CO2

Fermentation of one mole of glucose can produce two moles of ethanol, this kind of fermentaion is often called anaerobic fermentation.

lets see how to solve the question step wise,

First,

molecular weiight of glucose = 180.1559 g/mol

weight taken of glucose = 755.1 g

molecular weight of ethanol = 46.07 g/mol

we have seen 1 mole of glucose gives two mole of ethanol

therefore,

1 C6H12O6 = 2 C2H5OH

ethanol produced in gm is 386.192 gm

density p=m/V

V= volume

m= mass

V= m/p

mass = 386.192 gm = 0.386 Kg

p = 0.789 g/mL