What is the total energy in kj lost when 10 grams of benzene is condensed at 80.1 degrees Celsius, cooled to a melting point of negative 5.1 degrees Celsius and frozen to a solid. Heat of Fusion for benzene= 128 J/g, Heat of Evaporation for benzene= 395 J/g, Specific Heat of benzene= 1.95 J/g degree Celsius
Ti = 80.1
Tf = -5.1
Lv = 395.0 J/g
Heatreleasedto convert gas to liquid at 80.1 oC
Q1 = m*Lv
= 10.0g *395.0 J/g
= 3950 J
Cl = 1.95 J/g.oC
Heat released to convert liquid from 80.1 oC to -5.1 oC
Q2 = m*Cl*(Ti-Tf)
= 10 g * 1.95 J/g.oC *(80.1--5.1) oC
= 1661.4 J
Lf = 128.0 J/g
Heat released to convert liquid to solid at -5.1 oC
Q3 = m*Lf
= 10.0g *128.0 J/g
= 1280 J
Total heat released = Q1 + Q2 + Q3
= 3950 J + 1661.4 J + 1280 J
= 6891.4 J
Answer: 6891.4 J
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