Question

The ΔGo for conversion of ‘axial’ fluorocyclohexane with ‘equatorial’ fluorocyclohexane at 25 oC is -0.25 kcal/mol. Calculate the percentage of fluorocyclohexane molecules that have the fluoro substituent in an equatorial position at equilibrium.

So far I have gotten this, please tell me what I am doing wrong or how to calculate the Keq

ΔG^o = RT ln K_eq

-0.25 = (8.3145 J/K mol)(298 K)ln(Keq)

Keq = 0.999

Answer 1