Based on the thermochemical equation below, calculate the heat change when 46.7 g of H2O has formed.
2 NH3(g) + 5/2 O2(g) --> 2 NO(g) + 3 H2O(g) ∆Ho = -585 kJ/mol rxn
+4554 kJ |
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-506 kJ |
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+506 kJ |
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-1518 kJ |
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none of the numerical answers are correct |
Option second -506 KJ is correct
Change in the heat of the reaction is -506 KJ
We used simple stoichiometry to calculate change in heat of the reaction.
We have to round off the answer -505.9166 KJ to -506 KJ
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