Question

Having trouble with this lab. This is the table. I am trying to figure out the...

Having trouble with this lab. This is the table. I am trying to figure out the final reaction rate. Can someone please do one and give me a step by step so I can do the rest.

Data Table 1: Varying the Concentration of 1.0 M HCL

---- C o n c e n t r a t i o n s ----

#

drops

#

drops

# drops

Initial

Initial

Final

Final

Reaction Time (sec)

Reaction

Well

#

HCl

Water

Na2S2O3

HCl

Na2S2O3

HCl

Na2S2O3

Trial 1

Trial 2

Average

Rate (sec-1)

1

12

0

8

1M

0.3M

0.6M

0.12M

23.46

30.03

26.7

2

6

6

8

0.5M

0.3M

0.15M

0.12M

41.15

31.22

36.2

3

4

8

8

0.33M

0.3M

0.066M

0.12M

46.12

37.12

41.6

Homework Answers

Answer #1
Data Table 1: Varying the Concentration of 1.0 M HCL
---- C o n c e n t r a t i o n s ----
# # # drops Initial Initial Final Final Reaction Time (sec) Reaction
drops drops
Well HCl Water Na2S2O3 HCl (M) Na2S2O3 (M) HCl (M) Na2S2O3 (M) Trial 1 Trial 2 Average Rate (sec-1) (with HCl ) Rate (sec-1) (with Na2SO4 )
#
1 12 0 8 1 0.3 0.6 0.12 23.46 30.03 26.7 0.007490637 0.00674157
2 6 6 8 0.5 0.3 0.15 0.12 41.15 31.22 36.2 0.004834254 0.00497238
3 4 8 8 0.33 0.3 0.066 0.12 46.12 37.12 41.6 0.003173077 0.00432692

Acording to the reaction, for HCl, the process is:

rate = (-1/2)*((final[]-initial[])/average time)

Number 2, is the estequimetrical coefitient for the reaction, so you can see both results and look at there are very similar.

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