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Lactic acid builds up during exercise. A 1.00 gram sample of this acid required 25.88 mL...

Lactic acid builds up during exercise. A 1.00 gram sample of this acid required 25.88 mL of 0.4290 M NaOH to neutralize. What is the molar mass of lactic acid?

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Answer #1

No. of mole of NaOH = moarity volume of solution in liter

= 0.4290 M 0.02588 L = 0.01110252 mole

lactic acid is monoprotic acid react with NaOH with equimolar proportion. Thus in 1 gram of sample of lactic acid contain 0.01110252 mole of lactic acid.

1 gm lactic acid = 0.01110252 mole then 1 mole = 1 1 / 0.01110252 = 90.07 gm

molar mass of lactic acid = 90.07gm/mole

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