A compound has an M+ ion at 122 amu. There is no M+2 peak. The height of the M+1 peak is 8.8% of the height of the M+ peak. There are strong absorbances in the IR spectrum at 3500, 3050, and 2900 cm−1. The 1H NMR spectrum shows resonances downfield of 7 ppm. Draw a structure consistent with this information.
M+1 peak is mostly due to 13 C isotope .Relative abundance of M+1 peak with respect to M=8.8%As this isotope is present only in the percentage of 1.1 % compared to 12C.
So. no of carbon atoms can be calculated by equating =8.8/1.1=8 carbon atoms
strong absorbances in the IR spectrum at 3500 -C-H alkynyl
At 3050, =CH or sp2 carbon aromatic
and 2900 cm−1. C-H or sp3 carbon alkyl
structure Ar-CH2 -CCH
1H NMR spectrum shows resonances downfield of 7 ppm- aromatic ring present -C6H5-
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