Question

Calcium oxide can be used to "scrub" carbon dioxide from air.
CaO (s) + CO2 (g) --> CaCO3 (s)

What mass of CO2 could be absorbed by 1.85 g of ?

Mass = g CO2

What volume would this CO2 occupy at STP?

Volume = L CO2

Answer 1

Calcium oxide can be used to "scrub" carbon dioxide from air.
CaO (s) + CO₂ (g) --> CaCO₃ (s)

What mass of CO₂ could be absorbed by 1.85 g of CaO(s)

Molar mass of CaO=56.08 g/mol

So moles of CaO = 1.85 g / 56.08 g/mol = 0.033 moles

Now one mole of CaO reacts with one mole of CO₂

So 0.033 moles of CaO will react with 0.033 mole of CO₂

Mass of CO₂ = moles of CO₂ Molar mass of CO₂ = 0.033moles 44 g/mol = 1.5 g

What volume would this CO₂ occupy at STP?

T = 273.15 K

P = 1 atm

n = 0.033 mole

R = 0.082L atm mol^-1K^-1

V = nRT/P = (0.033 mole 0.082L atm mol^-1K^-1 273.15 K) / 1 atm = 0.74 L