Question

Calculate the number of Ag nanoparticle having a 5 nm radius.?

Calculate the number of Ag nanoparticle having a 5 nm radius.?

Homework Answers

Answer #1

Given radius of Ag, r = 5 nm = 5x10-9 m = 5x10-9x102 cm            since 1 m = 102 cm

                                         = 5x10-7 cm

Volume = V = (4/3) x π x r3

           = (4/3) x π x (5x10-7)3 cm3

           = 5.236x10-19 cm3

Density of silver , d = 10.49 g/cm3

So mass of silver is , m = density x volume

                                   = 10.49 g/cm3 x 5.236x10-19 cm3

                                   = 5.49x10-18 g                           

No of moles,n = Mass / Atomic weight

                    = 5.49x10-18 g / 107.9 (g/mol)

                    = 5.09x10-20 mol

No of atoms = number of moles x Avogadro's number

                   = 5.09x10-20 mol x 6.023x1023 (atoms/mol)

                   = 30.6x103 atoms

Therefore the number of Ag nanoparticle having a 5 nm radius is 30.6x103 atoms

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