Question

A sample of air occupies 2.60 L when the pressure is 2.40 atm.

(a) What volume does the sample occupy at 5.90 atm at the same temperature? _________L

(b) What pressure is required in order to compress it to 0.0970 L at the same temperature?___________atm

Answer 1

We know that PV = nRT

Where

T = Temperature ;P = pressure ; n = No . of moles ;R = gas constant ; V= Volume of the gas

As the gas remains the same , n will constant & T also kept constant

So PV = constant

Thereby PV = P'V'

Where

P = initial pressure =2.40 atm

V = initial volume = 2.60 L

P'= final pressure = 5.90 atm

V' = final volume = ?

Plug the values we get V' = (PV) / P'

                                     = ( 2.40x2.60) / 5.90

                                     = 1.06 L

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(b) PV = P'V'

Where

P = initial pressure =2.40 atm

V = initial volume = 2.60 L

P'= final pressure = ?

V' = final volume = 0.0970 L

Plug the values we get P' = (PV) / V'

                                     = ( 2.40x2.60) / 0.0970

                                     = 64.3 atm