Question

A 10 mL graduated pipet was calibrated using water at a temperature of 21.7 degrees celcius. The average mass of water delivered for five trials was 9.843 g.

a) What is the calibrated volume of this pipet?

b) What is the error in the pipet volume?

Show Caluculations and cirlcle answer.

Answer 1

Answer : -

1 ) Calibrated volume of the pipet is = 9.503 mL

2)   % Error = 4.964 %

Given,

volume of pipet = 10mL

average mass of water = 9.483 g

at 21.70C density of water = 0.997837 g/mL

and density = mass / volume ==> Volume = mass / density

average volume of water after five trials = 9.483 / 0 0.997837 = 9.503 mL

1 ) Calibrated volume of the pipet is = 9.503 mL

2) % Error =| [(actual volume - theoretical volume) / theoretical value] |

= | [ ( 9.503 - 10 ) / 10 ]*100 | = 4.964 %

==> % Error = 4.964 %