Question

In the titration of total acid with sodium hydroxide, NaOH, it was determined that 36.03 mL of 0.0980 M NaOH was needed to neutralize all the acid in a 10.0 mL aliquot of a powdered drink mix solution. Calculate the total moles of acid in the 10.0 mL aliquot of powdered drink mix solution. Calculate the total moles of acid in 250.0 mL of the powdered drink mix.

Answer 1

number of moles of NaOH = 36.03 * 10^-3 * 0.098

                        = 3.53 * 10^-3 moles

if 1 mole of NaOH neutralizes 1 mole of acid mix then,

number of moles of acid drink mix = 3.53 * 10^-3 moles

so the number of moles in 10 mL of the acid drink mix = 3.53 * 10^-3 moles

number of moles of acid drink mix in 250 mL = 3.53 * 10^-3 * 250/10 moles

number of moles of acid drink mix in 250 mL = 0.08825 moles