Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 2.71×10−3.
Solution :
Overall cell reaction is
X(s)+Y+(aq) -- > X+(aq)+Y(s)
n = Number of electrons involved =1
K = 2.71 E-3
We know
Delta G0 = - RTlnK
R = 8.314 J / (mol K )
T = 298.15 K (room T)
Ka is equilibrium constant for this reaction
Lets plug the values and get the Delta G0
Delta G0 = - [ 8.314 x 298.15 x ln (2.71 E-3)] J
= -(-14651.82 J )
= 14651.82 J
Now using it we get value of E0
Delta G0 = - nE0 F
Here Delta G0 is standard free energy change , n = number of electrons involved in overall reaction.
E0 standard electrode potential of cell. F is faraday’s constant value is 96500 C / mol
Lets find Delta G0
E 0 = - Delta G0/ n F
= - [14651.82 J / 1 x 96500 ] V
=- 0.152 V
So standard electrode potential of cell = 0.152 V
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