An aqueous solution of barium hydroxide is standardized by
titration with a 0.156 M solution of hydrochloric acid.
If 28.6 mL of base are required to neutralize 25.7 mL of the acid,
what is the molarity of the barium hydroxide solution?
ANSWER:
Molarity of hydrochloric acid (Acid) = 0.156 M
Normality of hydrochloric acid (Acid), N1 = 0.156 N {because it gives 1 H+}
Volume of hydrochloric acid (Acid), V1 = 25.7 mL
Volume of barium hydroxide (Base), V2 = 28.6 mL
Normality of barium hydroxide (Base), N2 = ?
At neutralisation point,
N2V2 = N1V1
N2 x 28.6 mL = 0.156 N x 25.7 mL
N2 = 0.140 N
Now, we know that
Normality = n x Molarity {where, n is H+/OH- release or taken by the compound}
In case of barium hydroxide, it gives 2 OH- ions. So,
Normality = 2 x Molarity
0.140 N = 2 x Molarity
Molarity = 0.070 M
Hence, the molarity of the barium hydroxide solution is 0.070 M.
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