Question

find the concentration of ammonia in the solution. A solution is prepared by dissolving 0.13mol of acetic acid and 0.13mol of ammonium chloride in enough water to make 1.0 L of solution.

Answer 1

ANSWER the reaction can be written as

1 CH3COOH    +     1 NH4CL     -------> 1 HCL + 1 NH4CH3COOH

O.13 MOLE            0.13 MOLE

1 MOLE OF ACETIC ACID REACTS WITH AMMONIUM CHLORIDE FORMS 1 MOLE HCL AND 1 MOLE AMMONIUM ACETATE

NH4CH3COOH  ------> NH3 + CH3COOH

1 MOLE OF AMMONIUM ACETATE DECOMPOSE TO FORM 1 MOLE OF AMMONIA AND 1 MOLE OF ACETIC ACID .

SO the number of mole of ammonia form = 0.13 mole

molarity = number of mole / volume in lit = 0.13 / 1 lit = 0.13 M