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Imagine a mixture of magnesium and titanium (iv) chloride with a total mass of 5.104kg. After...

Imagine a mixture of magnesium and titanium (iv) chloride with a total mass of 5.104kg. After the reaction between the two metals is complete, the mixture is inspected to determine that there is no magnesium remaining and 927 grams of titanium metal is collected. How many grams of magnesium were in the original mixture and how many grams of titanium (iv) chloride are left over?

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Answer #1

ans)

From above data that.

given information

Here we calculate the 927 g of Ti (atomic mass 47.8 g/mol)

1 mole of reacts with 2 moles of Mg to form 1 mole of Ti.

so 19.39 moles of Ti are obtained from 19.39 moles of

we get

moles of Mg

we know that

The atomic mass of Mg is 24.3 g/mol. The mass of Mg reacted

we know that the

The molar mass of is 189.8 g/mol.

The mass of reacted .

The mass of excess left over is

from above values we can written as

this is information about the above data

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