Calculate to identify the limiting reactant using 0.400 g p-aminophenol, and 0.450 mL of acetic anhydride. Hint: (o.554 g acetaminophen will be produced from 0.400 g p-aminophenol; while 0.720 g acetaminophen will be produced from 0.450 mL acetic anhydride).
0.554 g acetaminophen will be produced from 0.400 g p-aminophenol; while 0.720 g acetaminophen will be produced from 0.450 mL acetic anhydride.
Since, the amount of acetaminophen obtained from p-aminophenol is less than the amount of acetaminophen obtained from acetic anhydride p-aminophenol is the limiting reagent and acetic anhydride is the excess reagent.
Note:
p-aminophenol has molecular weight of 109.1 g/mol
Acetaminophen has molecular weight of 151.2 g/mol.
0.400 g p-aminophenol
0.00366 moles of p-aminophenol will give 0.00366 moles of acetaminophen which corresponds to
0.450 mL of acetic anhydride (density 1.05 g/ml)
Acetic anhydride has molar mass 102.1 g/mol.
Mass of acetic anhydride
0.00463 moles of acetic anhydride will give 0.00463 moles of acetaminophen which corresponds to
Get Answers For Free
Most questions answered within 1 hours.