Aqueous hydrochloric acid (HCl) will react with a solid sodium hydroide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water(H2O). Suppose 0.36 g of hydrochloric acid is mixed with 0.200 g of sodium hydroxide. Calculate the maximum mass of sodium chloride that could be produced by the chemical reaction. Round your answer to 3 sig figs.
balanced reaction equation
NaOH + HCl --- > NaCl + H2O
Using the given mass of each reactant we can find the amount of NaCl that can be formed
Calculating the mass of NaCl using the given mass of HCl
(0.36 g HCl * 1 mol / 36.5 g)*(1 mol NaCl / 1 mol HCl)*(58.443 g / 1 mol NaCl) = 0.576 g NaCl
Calculating the mass of NaCl using the given mass of NaOH
(0.200 g NaOH * 1 mol / 40.0 g)*(1 mol NaCl / 1 mol NaOH)*(58.443 g / 1 mol NaCl) = 0.292 g NaCl
Since the NaOH gives less mass of NaCl therefore the NaOH is limiting reactant and therefore the theoretical amount of the NaCl that can be formed is 0.292 g NaCl
Therefore mass of NaCl can be formed = 0.292 g
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