Question

Aqueous hydrochloric acid (HCl) will react with a solid sodium hydroide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water(H2O). Suppose 0.36 g of hydrochloric acid is mixed with 0.200 g of sodium hydroxide. Calculate the maximum mass of sodium chloride that could be produced by the chemical reaction. Round your answer to 3 sig figs.

Answer 1

Solution :-

balanced reaction equation

NaOH + HCl --- > NaCl + H2O

Using the given mass of each reactant we can find the amount of NaCl that can be formed

Calculating the mass of NaCl using the given mass of HCl

(0.36 g HCl * 1 mol / 36.5 g)*(1 mol NaCl / 1 mol HCl)*(58.443 g / 1 mol NaCl) = 0.576 g NaCl

Calculating the mass of NaCl using the given mass of NaOH

(0.200 g NaOH * 1 mol / 40.0 g)*(1 mol NaCl / 1 mol NaOH)*(58.443 g / 1 mol NaCl) = 0.292 g NaCl

Since the NaOH gives less mass of NaCl therefore the NaOH is limiting reactant and therefore the theoretical amount of the NaCl that can be formed is 0.292 g NaCl

Therefore mass of NaCl can be formed = 0.292 g