How would I measure out 25% dichloromethane and 25% hexane in a 25mL vial? Is that just 12.5mL of each solvent?
Same thing for 50% DCM/hexane in a 50mL vial. Is that just 25mL DCM and 25mL hexane?
Yes, your assumption is correct. In both the cases, the given percentages can be considered as 1:1.
In case of 25 % dichloromethane (DCM), and 25 % hexane in 25 mL vial, you can take any amount lesser than 12.5 mL of each solvent (since the maximum capacity of the vial is 25 mL) but with equal amounts (lets say 1 mL of DCM and 1 mL of hexane and so on up to 12.5 mL of DCM and 12.5 mL of hexane.
Same is the case with 50 % DCM and hexane. You can take any amount of solvent (maximum 25 mL since the capacity of the vial is 50 mL) from 1 to up to 25 mL each.
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