Question

What is the concentration of magnesium bromide, in ppm, if 100.34 g MgBr 2 is dissolved in 4.57 L water. Record your answer in scientific notation to 3 significant figures.

Answer 1

Concentration of MgBr₂ = 2.20 x 10⁴ ppm          ( if wrong then try 2.15 x 10⁴ ppm)

Explanation

Mass of MgBr₂ = 100.34 g

Mass of MgBr₂ = 100.34 x 10³ mg

Volume of solution = 4.57 L

concentration of MgBr₂ = (Mass of MgBr₂) / (Volume of solution)

concentration of MgBr₂ = (100.34 x 10³ mg) / (4.57 L)

concentration of MgBr₂ = 21956.24 mg/L

concentration of MgBr₂ = 21956.24 mg/L * (1 ppm / 1mg/L)

concentration of MgBr₂ = 21956.24 ppm

concentration of MgBr₂ = 2.20 x 10⁴ppm