Question

What is the molar solubility BaCO₃ in pure water? (K_sp = 5.1*10^-9)

Answer = 7.1 * 10^-5M

Answer 1

BaCO₃(s) Ba²⁺⁽aq) + CO3^2–(aq)

I            -          0                0

C           -         +x              +x                 x = solubility of BaCO3

E           -           x                x

Ksp = [Ba2+][CO3^2–]

5.1 x 10–9 = (x)(x)

5.1 x 10–9 = x2

7.1 x 10–5 M = x = solubility of BaCO3