Small quantities of hydrogen can be prepared by the addition of hydrochloric acid to zinc. A sample of 195 mL of hydrogen was collected over water at 25°C and 753 torr. What mass of hydrogen was collected? (Pwater = 24 torr at 25°C)
Given : volume of H2 gas = 195 mL
T = 25 deg C= 25.0 degC + 273.15 = 298.15 K
Pressure= 753 torr
We know total pressure = pressure of H2 gas + pressure of H2O vapor
Lets subtract the pressure of water from total pressure to get pressure of H2 gas
Pressure of H2 gas = 753 torr – 24 torr
= 729 torr
Lets find moles of H2
To get mol of H2 we use ideal gas equation.
n = pV / RT
here value of R is L atm per K per mol
R = 0.0821 L atm per K per mol
T in K
We convert pressure to atm
Pressure in atm
=729 torr 8 * 1 atm / 760 torr
= 0.9592 atm
n = 0.9592 atm * 0.195 L / ( 0.0821 L atm per K per mol * 298.15 K )
= 0.00764 mol H2
We use molar mass to get mass of H2
Mass of H2 in g
= mol of H2 * molar mass of H2
= 0.00764 mol H2* 2.016 g per mol / mol H2
= 0.0154 g H2
Mass of H2 collected = 0.0154 g
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