Question

How many mL of 0.1 M NaOH must be added to 40 mL of 0.06 F...

How many mL of 0.1 M NaOH must be added to 40 mL of 0.06 F tri-protic acid solution to reach a pH equal to pKa3?

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Homework Answers

Answer #1

60ml

Explanation

If triprotic acid is represented by H3A

when pH = pKa3

[A3-] = [ HA-]

H3A + NaOH ------> NaH2A : Volume of NaOH required = (40ml × 0.06M)/0.1M = 24ml

NaH2A + NaOH ------> Na2HA : Volume of NaOH required = 24ml

Na2HA + NaOH -----> Na3A: this reaction should be completed 50% only to get pH = pKa3 , volume of NaOH required = 12ml

Therefore,

Volume required to get pH = pKa3 in triprotic acid vs NaOH titration = 24ml + 24ml + 12ml = 60ml

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