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what is the experimental molar mass of potassium hydrogen phthalate if a solution containing 1.862 g...

what is the experimental molar mass of potassium hydrogen phthalate if a solution containing 1.862 g is titrated completely by 27.21 ml of .3369 M NaOH? I know the answer is 203.1 g/mol but how do you get to that answer?

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Answer #1

Calculate mole of NaOH

no. of mole = molarity voume of solution in liter

no. of mole of NaOH = 0.3369 M   0.02721 L = 0.009167049 mole

NaOH react with potassium hydrogen phthalate in equimolar proportion thus to react with 0.009167049 mole of NaOH require 0.009167049 mole of potassium hydrogen phthalate.

that mean 1.862 gm of potassium hydrogen phthalate = 0.009167049 mole of potassium hydrogen phthalate

then 1 mole of potassium hydrogen phthalate = 1 1.862 / 0.009167049 = 203.1 gm/mole

therefore molar mass of potassium hydrogen phthalate = 203.1 gm/mole

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