Question

How much heat in kilojoules is required to warm 10.0 g of ice, initially at -10.0 ∘C, to steam at 125 ∘C. The heat capacity of ice is 2.09 J/g∘C and that of steam is 1.84 J/g∘C.

Answer #1

mass of ice = 10.0 g

moles of ice = 10 / 18.02 = 0.555

-10.0 °C ----------> 0.0 °C ------------> 100.0 °C -------------> 125.0 °C

1 2 3 4 5

in this process 5 conversions are required.

Q1 = m Cp dT = 10 x 2.09 x (10) = 209 J

Q2 = n x delta H fusion = 0.555 x 6.01 x 10^3 = 3335.55 J

Q3 = m Cp dT = 10 x 4.18 x (100 ) = 4184 J

Q4 = n x delta H vap = 0.555 x 40.7 x 10^3 = 22588.5 J

Q5 = m Cp dT = 10 x 1.84 x (125 - 100) = 460 J

total heat = Q1 + Q2 + Q3 + Q4 + Q5

**= 30777 J**

**total heat = 30.8 kJ**

How much heat (in kJ) is required to warm 13.0 g of ice,
initially at -10.0 ∘C, to steam at 109.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

How much heat (in kJ) is required to warm 12.0 g of ice,
initially at -10.0 ∘C, to steam at 111.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

How much heat (in kJ) is required to warm 13.0 g of ice,
initially at -10.0 ∘C, to steam at 113.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

12.67
How much heat (in kJ) is required to warm 10.0 g of ice,
initially at -13.0 ∘C, to steam at 112.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

How much heat (in KJ) is required to warm 13.0 g of ice,
initially at -10.0 *C, to steam at 113.0 degress C? The heat
capacity of ice is 2.09 J/g degress C and that of steam is 2.01 J/g
* C. Show work.

A) How much heat (in kJ) is required to warm 13.0 g of ice,
initially at -14.0 ∘C, to steam at 114.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C
B) How much heat is evolved in
converting 1.00 mol of steam at 130.0 ∘C to ice at -50.0 ∘C? The
heat capacity of steam is 2.01 J/(g⋅∘C) and of ice is 2.09
J/(g⋅∘C).

How much heat (in kJ) is required to warm 12.0 g of ice,
initially at -12.0 ∘C, to steam at 112.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C. kJ

5. How much heat (in kJ) is required to warm 10.0 g of ice,
initially at -10.0

part A How much heat energy, in
kilojoules, is required to convert 69.0 g of ice at −18.0 ∘C to
water at 25.0 ∘C ? Part B How long would it take
for 1.50 mol of water at 100.0 ∘C to be converted completely into
steam if heat were added at a constant rate of 22.0 J/s ?
Specific heat of ice: sice=2.09 J/(g⋅∘C)
Specific heat of liquid water: swater=4.18 J/(g⋅∘C)
Enthalpy of fusion (H2O(s)→H2O(l)): ΔHfus=334 J/g
Enthalpy of vaporization (H2O(l)→H2O(g)):...

How much heat energy, in kilojoules, is required to convert 46.0
g of ice at −18.0 ∘C to water at 25.0 ∘C ? Express your answer to
three significant figures and include the appropriate units.
The constants for H2O are shown here:
Specific heat of ice: sice=2.09 J/(g⋅∘C)
Specific heat of liquid water: swater=4.18 J/(g⋅∘C)
Enthalpy of fusion (H2O(s)→H2O(l)): ΔHfus=334 J/g
Enthalpy of vaporization (H2O(l)→H2O(g)): ΔHvap=2250
J/g

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