Find the temperature (in K) above which a reaction with a delta H
of 123.0 kJ/mol and a delta S of 90.0 J/K×mol becomes spontaneous.
Use four significant figures.
T=________K
We have the Gibbs- Helmholtz relation of free energy and enthalpy, entropy as
delta G = delta H - T. delta S
and at equilibrium the delta G becomes zero.
For the given reaction both delta H and delta S are positive, it is entropy driven and becomes spontaneous at higher temperatures.( reaction is endo thermic.)
Let us find the temperature above which the given reaction becomes spontaneous as
T= deltaH/ delta S
= [123x1000J/mol] / [ 90J/K.mol]
= 1366.66K
Thus above 1366.67 K the reaction becomes spontaneous.
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