Question

What is the concentration (M) of CH3OH in a solution prepared by dissolving 14.4 g of CH3OH in sufficient water to give exactly 230 mL of solution?

Answer 1

Answer – Given, mass of CH₃OH = 14.4 g , volume = 230 mL

First we need to calculate the moles of CH₃OH

Moles of CH₃OH = given mass / molar mass

                            = 14.4 g / 32.04 g.mol^-1

                            = 0.449 moles

We know concentration (M) of CH3OH in a solution

[CH₃OH] = 0.449 moles / 0.230 L

                = 1.95 M