Question

Balance the following chemical reaction:

C2H5OH + O2 + NH3 --> CH2N0.2O0.5 + CO2 + H2O

Respiratory Quotient = 0.6

ROUND ANSWERS TO 2 DECIMAL PLACES. DO NOT FORGET LEADING ZEROS.

Answer 1

In the righ hand side N atom is 0.2 and so we need 0.2 moles of NH₃. Doing so we get total H in LHS is 6+0.2*3=6.6

In RHS we have 2 H in CH₂N_0.2O_0.5. So additional H required is 4.6. Thus 2.3 moles of H₂O will be required in RHS.

Now total oxygen in RHS is 0.5+2+2.3=4.8

So we have to take 1.90 moles of O₂ which contains 3.8 O atom and one O atom is present in ethyl alcohol

Thus the balanced chemical equation is

C₂H₅OH+1.90 O₂+0.2 NH₃=CH₂N_0.2O_0.5+CO₂+2.30 H₂O