Question

Which of the reactions favor formation of the products? Check all that apply. Check all that apply. H3C−CH3+H2C=CH−⇌H3C−CH2−+H2C=CH2; H2C=CH2+HC≡C−⇌H2C=CH−+HC≡CH; HC≡CH+H3C−CH2−⇌HC≡C−+H3C−CH3

Answer 1

H3C−CH3+H2C=CH−⇌H3C−CH2−+H2C=CH2
negative charge is more stable on H2C=CH− as compared to H3C−CH2− because negative charge on Sp2 hybridised carbon is more stable than than on SP3
product is not favourable

H2C=CH2+HC≡C−⇌H2C=CH−+HC≡CH
negative charge is more stable on sp carbon that on sp2 carbon
So HC≡C− is more stable than H2C=CH−
product is not favourable

HC≡CH+H3C−CH2−⇌HC≡C−+H3C−CH3
negative charge is more stable on sp carbon that on sp3 carbon
So HC≡C− is more stable than H3C−CH2−
Here product is more stable
Answer: 3rd reaction favours formation of product