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Part B Arrange the following ionic compounds in order of decreasing amount of energy released in...

Part B Arrange the following ionic compounds in order of decreasing amount of energy released in lattice formation: LiF, MgS, InN, and RbBr. Rank from greatest to least lattice energy. To rank items as equivalent, overlap them.

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Answer #1

The correct order will be

RbBr < LiF < MgS < InN

Reason: The charge on In and N will be +3 and -3 which will lead to very high amount of lattice energy as compared to Mg and S where the charge on the cation is equal to 2 and the charge on anion is equal to -2

Similarly, the charge on LiF and RbBr will be +1 and -1 respectively, but since the size of Li+ is very small it has very high value of lattice energy

Hence the correct order is RbBr < LiF < MgS < InN

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