A buffer solution is 0.310 M in H2CO3 and 0.291 M in KHCO3. If Ka1 for H2CO3 is 4.2x10^-7 , what is the pH of this buffer solution?
PKa = -logKa
= -log4.2*10^-7
= 6.3767
[H2CO3] = 0.310M
[KHCO3] = 0.291M
PH = PKa + log[KHCO3]/[H2CO3]
= 6.3767 + log0.291/0.310
= 6.3767 -0.02747 = 6.35 >>>>answer
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