Question

Determine the concentrations of BaBr2, Ba2 , and Br– in a solution prepared by dissolving 2.51 × 10–4 g BaBr2 in 2.50 L of water. Express all three concentrations in molarity. Additionally, express the concentrations of the ionic species in parts per million (ppm).

Answer 1

concentrations of BaBr2 =

M =n/ V (l)                                                                         

n = w/m = 2.51*10^-4/137+16 =2.51*10^-4 /297

m = 2.51*10^-4 /297 *2.5

    = 0.0033*10^-4

     = 3.3 *10^-4

^{this is the concentration of BaBr2}

BaBr2    ---------->      Ba⁺²           +       2Br^-

3.3*10^-7m                   3.3*10^-7m    2 * 3.3*10^-7m   

                                                                              = 6.6*10^-7m

this is concentration of three.