Question

I am doing a report on SN2 reactions and have the mols of the Nucleophile ( Sodium Acetate 0.0110 mol) and electrophile (1-Bromopropane 0.0183 mol) I the mass of the propylacetate i have for the product is 0.533g. I am supposed to calculate the final yield, but I'm not sure if this means the theoretical yield or what.

Answer 1

I think you are getting a wrong product.

The actual product is n-butyl acetate.

Assuming the mass. Of propylacetate being the mass of the actual product n-butyl acetate, we will calculate:

Actual yield of product= 0.553 g.

Theoretical yield:

According to the reaction equation,

1 mole of 1-Bromopropane reacts with 1 mole of sodium acetate yields 1 mole of n-butyl acetate.

Therefore, 0.0110 mole of sodium acetate and 0.0183 mole of 1-bromopropane yields 0.0110 mole of n-butyl acetate. (As sodium is limiting reagent).

Mole of n-butyl acetate= 0.0110 mol

Mass of n-butyl acetate= molar mass× moles= 116× 0.0110 g

= 1.276 g.

Now, percentage yield= (actual yield/theoritical yield)× 100

= .(0.533/1.276)× 100

= 41.77%

Hope it helps.