Question

For the following fusion reaction, calculate the change in energy of the reaction in units of joules per mole.

2/1 H + 2/1H --> 3/1 H + 1/1 H

H-1                1.00782

H-2               2.0140

H-3               3.01603

H-4               4.00260

neutron         1.00866

Answer 1

The equation: (Change in E) = (c^2) (change in m)

c = the speed of light, 3x10^8 m/s
(change in m) = (mass of products) - (mass of reactants) Kg

1 mol contains 6.03 x 10^23 particles, so 1 mol H-1 weighs 1.00782 x1.6605x10^-27x6.03x10^23kg
=1.00911152 x 10^-3 kg amu Avogadro N

2H-1 = twice the above > H-2 2.014x1.00782 x1.6605x10^-27 x 6.03 x 10^23=2.0X10^-3kg

Loss of mass = [2.01822304 - 2.0165]x10^-3kg

=1.7x10^-3kg

E = mc^2

=1.7x10^-6 x (3x10^8)²

=1.7x10^-6 x 9x10^16

=1.53x10^9 j/mole