Question

Go to the Slightly Soluble Salts tab. Set the volume to 1.0×10−16 L . Select the salt mercury bromide from the dropdown menu. In the text box provided, set the total number of ions under the data for "cations" to 16 to make the solution saturated. Calculate the solubility in M of mercury bromide for a saturated solution.

Answer 1

HgBr2 ----------------------> Hg+2 + 2Br-

number of Hg ions = 1

moles of Hg ions = number of ions / avagadro number

                           = 16 / (6.023 x 10^23)

                           = 2.66 x 10^-23

volume is given = 1.0 x 10^-16 L

molarity = moles / volume

             = 2.66 x 10^-23 mol / 1.0 x 10^-16 L

            = 2.66 x 10^-7 M

solubility = 2.66 x 10^-7 M