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If 14.5 g of sulfuric acid in "f" reaction above reacts with excess boron hydroxide, how...

If 14.5 g of sulfuric acid in "f" reaction above reacts with excess boron hydroxide, how much water will be produced in grams?

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Answer #1

Balanced reaction between sulfuric acid and boron hydroxide is,

3H2SO4 + 2B(OH)3 -------------> B2(SO4)3 + 6H2O

=> 3 moles of Sulfuric acid produces 6 moles of water.

      That means 3 * 98 = 294 g of sulfuric acid produces 6*18 = 108 g of water.

294 g ------------------> 108 g

14.5 g ----------------> ?

= 14.5 * 108 / 294

= 5.33 g   <<<<<<<<---------------(ANSWER)

Therefore, 14.5 g of sulfuric acid produces 5.33 g of water

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