Explaining why, which, if any, of the following water solutions will have the lowest freezing temperature ? Explain the reason for your answer. A. 0.20m NaCl B. 0.10m AlCl3 C. 0.40m KBr D. 0.20m CaCl2
More the number ions produced on dissociation will have higher the depression in freezing point
Depression in freezing point() directly proporional to number of ions (i) along with molality of the solution
Let us find which has high molality of ions
A) NaCl(aq) ---> Na+(aq) + Cl-(aq)
Complete dissociation of 0.2m NaCl gives 0.2 m Na+ and 0.2 m Cl- ions
Total molality of ions = 0.2m Na+ + 0.2m Cl- ions = 0.4 m ions
B) 0.10m AlCl3
AlCl3(aq) ---> Al3+(aq) + 3Cl-(aq)
Total molality of ions = 0.1m Al3++ 3( 0.1 ) m Cl-ions = 0.4 m ions
C) 0.40m KBr
KBr(aq) ---> K+(aq) + Br-(aq)
Total molality of ions = 0.4 m Na+ + 0.4 m Cl- ions = 0.8 m ions
D) 0.20m CaCl2
CaCl2(aq) ---> Ca2+(aq) + 2Cl-(aq)
Total molality of ions = 0.2 m Ca2+ + 2(0.2 m) Cl- = 0.6 m ions
Answer is C) KBr is giving high molality of ions so it will have highest depression in freeziing point.
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