Question

For a different reaction, Kc = 1.92×103, kf=6.92×104s−1, and kr= 36.1 s−1 . Adding a catalyst increases the forward rate constant to 1.09×107 s−1 . What is the new value of the reverse reaction constant, kr, after adding catalyst?

Answer 1

We know that the equilibrium constant value Kc doesn’t changed even after adding the catalyst

i.e, catalyst do not change the equilibrium constant Kc value.

So from given data we have,

Kc = 1.92 x 10³ and forward reaction constant ( after adding the catalyst) kf = 1.09x10⁷ s^-1

We know that Kc = kf / kr => reverse reaction constant kr= kf / Kc

Substituting the values we have kr = 1.09x10⁷ s^-1 / 1.92 x 10³ = 5.68 x 10³ s^-1

Therefore, the new value of reverse reaction constant (kr) after adding catalyst is 5.68 x 10³ s^-1