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The thermal decomposition of acetaldehyde, CH3CHO --> CH4 + CO, is a second-order reaction. The rate...


The thermal decomposition of acetaldehyde, CH3CHO --> CH4 + CO, is a second-order reaction. The rate constant is 1.55x10-4 M-1s-1 at 25oC. If the initial concentration of CH3CHO is 0.250M. What will the concentration be after 2.50 hours?

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Answer #1

Given that you have a second order reaction, and that it corresponds to the decomposition of a unique compound, you must consider this compound is the only one reacting as a second order. The formula you must use is

;

where [A] stands for concentration of the compound of interest, k is the reaction rate constant and t is the time.

Knowing this, you can first substitute as follows:

Consider that the time you were given must be changed to seconds, for the constant you were given is in s-1.

Solving for [A]:

This is the concentration after 2.5h have elapsed.

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