Question

Tin(IV) chloride is produced in 46.9% yield by the reaction of tin with chlorine. How much...

Tin(IV) chloride is produced in 46.9% yield by the reaction of tin with chlorine. How much tin, in kilograms, is required to produce 6.484 kilogram of tin(IV) chloride?

The answer is 6.30 Kg but I keep getting 592 g

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Answer #1

actual yield of SnCl4 = 6.484Kg = 6484g

percentage yield        = 46.9%

percent yield    = acutual yield*100/theoritical yield

46.9                = 6484*100/theoritical yield

theoritical yield   = 6484*100/46.9   = 13825g

Sn + 2Cl2 ------------------> SnCl4

1moles of SnCl4 produced from 1 moles of Sn

260.5g of SnCl4 produced from 118.7g of Sn

13825g of SnCl4 produced from = 118.7*13825/260.5 = 6300g   = 6.3Kg of Sn >>>>answer

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