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how many mol of iron are needed to produce 7.4 mol iron (III) oxide

how many mol of iron are needed to produce 7.4 mol iron (III) oxide

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Answer #1

The compound is:
Fe2O3

For 1 mol of Fe2O3, we need 2 moles of Fe

So,
number of moles of Fe required= 2* number of moles of Fe2O3
                                              = 2*7.4 mol
                                              = 14.8 mol

Answer: 14.8 mol

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