We will use Nernst equation to solve for concentration gradient.
V = - (RT/zF) ln ci/co
Where, V is voltage across membrane = 100 mV = 0.1 V
R is gas constant = 8.314 J/(mol.K)
T is temperature in K = 37C = 310.15 K
z is valence of ion = we will consider as 1 (not mentioned in Question)
F is Faraday’s constant = 9.646*10^4 C/mol
ci/co is ratio of inside and outside concentration = ?
Let us put the values in equation.
0.1 V = - (8.314*310.15/1*9.645*10^4) ln ci/co
= - (2578.6/9.645*10^4) ln ci/co
0.1 V = - 0.0267 ln ci/co
Ci/co = 0.0236
Ratio of concentrations is 0.0236 which may be ≈ 0
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